sar output with date

sar(1) output displays the time only, printing the date in the header. Here's something to include the date per line:

#!/bin/ksh

for F in "$@"; do sar -f $F; done | sed -n -e '
/\/[789][0-9]$/ { s:.*\(..\)/\(..\)/\(..\)$:19\3-\1-\2:; h; }
/\/[0-6][0-9]$/ { s:.*\(..\)/\(..\)/\(..\)$:20\3-\1-\2:; h; }
/\/[0-9]\{4\}$/ { s:.*\(..\)/\(..\)/\(....\)$:\3-\1-\2:; h; }
/%usr  *%sys  *%wio  *%idle/ { s/^[^ ]*/               when/; p; }
/^[0-9][0-9]:[0-9][0-9]:[0-9][0-9]  *[0-9]/ { H; x; s/\n/ /; p; s/ .*//; h; }'

That's some horrible y2k work in there.

Am I the only one that wants a prepend command? The last line is an append, swap, print, then restore and push back to the hold space... i.e. a prepend!!

(I know awk might've been better suited. I was bored and wanted to sed.)